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The correct of decreasing second ionisat...

The correct of decreasing second ionisation enthalpy of `Ti(22),V(23),Cr(24)` and `Mn(25)` is

A

`V gt Mn gt Cr gt Ti`

B

`Mn gt Cr gt Ti gt V `

C

`Ti gt V gt Cr gt Mn`

D

`Cr gt Mn gt V gt Ti`

Text Solution

Verified by Experts

The correct Answer is:
d

`._(22)Ti : 3s^(2),4s^(2) overset(IE_(1))` to `3d^(2),4s^(1)`
`._(23)V : 3d^(3),4s^(2) overset(IE_(1))` to `3d^(3),4s^(1)`
`._(24)Cr : 3d^(5),4s^(1) overset(IE_(1))(rarr)` to `3d^(5) overset(IE_(2)from)underset(half-"filled")(rarr)` maximum
` ._(25)Mn : 3d^(5),4s^(2) overset(IE_(1)) to 3d^(5),4s^(1)`
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