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The correct order of increasing bond ang...

The correct order of increasing bond angle in the following species is

A

`Cl_(2)O lt ClO_(2) lt ClO_(2)^(-)`

B

`ClO_(2) lt Cl_(2)O lt ClO_(2)^(-)`

C

`Cl_(2)O lt ClO_(2)^(-) lt ClO_(2)`

D

`ClO_(2)^(-) lt Cl_(2)O lt ClO_(2)`

Text Solution

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The correct Answer is:
To determine the correct order of increasing bond angles in the given species (ClO2^-, ClO2, and Cl2O), we will analyze each molecule's structure and the factors affecting their bond angles. ### Step-by-Step Solution: 1. **Identify the Valence Electrons**: - For ClO2^- (Chlorite ion): Chlorine (Cl) has 7 valence electrons, and each oxygen (O) has 6. The negative charge adds one extra electron. Therefore, total = 7 + 2(6) + 1 = 20 valence electrons. - For ClO2 (Chlorine dioxide): Chlorine has 7 valence electrons, and each oxygen has 6. Total = 7 + 2(6) = 19 valence electrons. - For Cl2O (Dichlorine monoxide): Each chlorine has 7 valence electrons, and oxygen has 6. Total = 2(7) + 6 = 20 valence electrons. 2. **Determine the Steric Number**: - For ClO2^-: There are 2 bond pairs (Cl=O) and 2 lone pairs on chlorine. Steric number = 2 (bond pairs) + 2 (lone pairs) = 4. - For ClO2: There are 2 bond pairs and 1 lone pair on chlorine. Steric number = 2 + 1 = 3. - For Cl2O: There are 2 bond pairs (Cl-O) and 2 lone pairs on oxygen. Steric number = 2 + 2 = 4. 3. **Geometry and Bond Angles**: - For ClO2^-: With a steric number of 4 and 2 lone pairs, the geometry is based on a tetrahedral arrangement. The bond angle is slightly less than 109.5° due to lone pair repulsion, approximately 110°. - For ClO2: With a steric number of 3 and 1 lone pair, the geometry is bent. The bond angle is larger than 120° due to the presence of a double bond and lone pair repulsion, approximately 118°. - For Cl2O: With a steric number of 4 and 2 lone pairs, the geometry is also based on a tetrahedral arrangement. The bond angle is slightly less than 109.5°, approximately 111°. 4. **Comparing Bond Angles**: - ClO2^- has a bond angle of approximately 110°. - Cl2O has a bond angle of approximately 111°. - ClO2 has a bond angle of approximately 118°. 5. **Order of Increasing Bond Angles**: - The order of increasing bond angles is: ClO2^- < Cl2O < ClO2. ### Final Answer: The correct order of increasing bond angles in the species is: **ClO2^- < Cl2O < ClO2**.

To determine the correct order of increasing bond angles in the given species (ClO2^-, ClO2, and Cl2O), we will analyze each molecule's structure and the factors affecting their bond angles. ### Step-by-Step Solution: 1. **Identify the Valence Electrons**: - For ClO2^- (Chlorite ion): Chlorine (Cl) has 7 valence electrons, and each oxygen (O) has 6. The negative charge adds one extra electron. Therefore, total = 7 + 2(6) + 1 = 20 valence electrons. - For ClO2 (Chlorine dioxide): Chlorine has 7 valence electrons, and each oxygen has 6. Total = 7 + 2(6) = 19 valence electrons. - For Cl2O (Dichlorine monoxide): Each chlorine has 7 valence electrons, and oxygen has 6. Total = 2(7) + 6 = 20 valence electrons. ...
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