Noble gases have compleately filled valance shall i.e. `m^(2)sp^(2)` exceps He (i.e) .Noble gases are monoomic under normal conductions .Law bolding point of the ligher noble gases are due to weak van dor wads forces between the atoms and abance of any interature imaractions `Xe` reacts with `F_(2)` so give a sourceof fouoxide mently `XeF_(2),XeF_(4),XeF_(4),XeF_(3)` on complete hydrolyes gives `XeFe_(3)`,
Structure of `XeF_(4)` is

Options

A. linear
B. pyramidal
C. tetrahedral
D. squre planner

Answer

d

Explanation

`XeF_(4)` molecule has `Xe` `sp^(2) d^(2)` hydridized and its shape is square planar due to the presence of two lone pair of electrons