The molecule of `CO_(2)` has `180^(@)` bond angle it one be explained on the basic of

Options

A. `sp^(3)` hydridisation
B. `sp^(2)` hydridisation
C. `sp` hydridisation
D. `d^(2)sp^(3)` hydridisation

Answer

c

Explanation

`C_("ground state") = 2s^(2),2p_(x)^(1)2p_(y)^(1)` :
`C_("excited state") = 2s^(2),2p_(x)^(1)2p_(y)^(1)2p_(z)^(1)` :
`O_("ground state") = 2s^(2),2p_(x)^(2)2p_(y)^(1)2p_(z)^(1)` :
In the formation of `CO_(2)` molecule of orbital, hybridization of orbitals of carbon occure to a limited exted involving only one x and ane p orbitals .There is this sp this sp hybridisation of vilence shell orbitals of the casrbon atom resulting in the formation of two sp hybrid orbitals.