In an octahedral structure , the pair of d orbitals involved in `d^(2)sp^(2)` hybridization is

Options

A. `d_(x^(2)),d_(xz)`
B. `d_(xy),d_(yz)`
C. `d_(x^(2) - y^(2)),d_(z^(2))`
D. `d_(xz),d_(x^(2) - y^(2))`

Answer

c

Explanation

In the formation of `d^(2)sp^(2)` hybrid orbital two `(n - 1)d` orbitals of e.g. set (i.e. `(n - 1)dz^(2) and (n - 1)dx^(2) - y^(2)` orbitals ) one ns three np [np,np, and np] orbitals combine togather and form six `d^(2)sp^(2)` hydral orbitals .