Which of the following carboxylic acid can undergo deccarboxylation on simple heating even in the absence of soda lime ?

Options

A.
B.
C.
D.

Explanation

To determine which carboxylic acid can undergo decarboxylation on simple heating without the need for soda lime, we will analyze each option provided in the question.

### Step-by-Step Solution:

1. **Understanding Decarboxylation**:
Decarboxylation is a chemical reaction that involves the removal of a carboxyl group (-COOH) from a carboxylic acid, resulting in the formation of an alkane. This reaction can be facilitated by soda lime (a mixture of sodium hydroxide and calcium oxide), but some compounds can undergo decarboxylation even without it.

2. **Analyzing the Options**:
- **Option A**: This carboxylic acid requires soda lime for decarboxylation. Without it, simple heating will not lead to the removal of the -COOH group. Therefore, this option is not correct.

- **Option B**: Similar to Option A, this compound also requires soda lime for decarboxylation. Simple heating will not suffice to remove the -COOH group. Thus, this option is also not correct.

- **Option C**: This carboxylic acid has a structure that allows for resonance stabilization. The presence of a nitro group (NO2) adjacent to the carboxyl group can facilitate the removal of the -COOH group through resonance effects. This means that upon simple heating, the -COOH group can be removed without the need for soda lime. Therefore, this option is a strong candidate for decarboxylation.

- **Option D**: Similar to Options A and B, this carboxylic acid also requires soda lime for decarboxylation. Simple heating will not lead to the removal of the -COOH group. Hence, this option is not correct.

3. **Conclusion**:
After analyzing all the options, we conclude that **Option C** is the only carboxylic acid that can undergo decarboxylation on simple heating even in the absence of soda lime due to the resonance stabilization provided by the adjacent nitro group.

### Final Answer:
**Option C** is the correct answer.

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