`(CH_(3))_(3)COH+CH_(3)MgBr rarr` Hydrocarbon `(A),(A)` is

Options

A. (a) `(CH_(3))_(3)C C H_(3)`
B. (b) `(CH_(3))_(3)CH`
C. (c) `CH_(4)`
D. (d) none of these

Explanation

To solve the given reaction `(CH₃)₃COH + CH₃MgBr`, we need to analyze the interaction between the alcohol and the Grignard reagent. Here’s a step-by-step breakdown of the reaction:

### Step 1: Identify the Reactants
The reactants are:
- **Tert-butyl alcohol**: `(CH₃)₃COH`
- **Methylmagnesium bromide**: `CH₃MgBr`

### Step 2: Understand the Reaction
Grignard reagents (like `CH₃MgBr`) are strong nucleophiles and react with electrophiles. In this case, the alcohol `(CH₃)₃COH` will react with the Grignard reagent.

### Step 3: Reaction Mechanism
1. The hydroxyl group (-OH) in tert-butyl alcohol is acidic. The Grignard reagent will deprotonate the alcohol, leading to the formation of tert-butoxide ion `(CH₃)₃CO⁻`.
2. The methyl group from the Grignard reagent will bond with the oxygen of the tert-butoxide ion.

### Step 4: Products Formation
The reaction can be summarized as follows:
- The hydrogen from the hydroxyl group of tert-butyl alcohol is replaced by the methyl group from the Grignard reagent.
- This results in the formation of methane (CH₄) and tert-butyl methyl ether `(CH₃)₃COCH₃`.

### Step 5: Write the Final Products
The final products of the reaction are:
- **Methane (CH₄)**
- **Tert-butyl methyl ether**: `(CH₃)₃COCH₃`

### Conclusion
Thus, the hydrocarbon `(A)` formed in the reaction is **methane (CH₄)**.

### Final Answer:
The hydrocarbon `(A)` is **CH₄ (methane)**.

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