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Alkyne can be reduced to alkenes by hydr...

Alkyne can be reduced to alkenes by hydrogenation in presence of

A

Ranyey `Ni`

B

Anhy. `AlCl_(3)`

C

`Pd`

D

Lindlar's catalyst

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The correct Answer is:
To solve the question "Alkyne can be reduced to alkenes by hydrogenation in presence of," we will analyze the options provided and determine which one is suitable for the reduction of alkynes to alkenes. ### Step-by-Step Solution: 1. **Understanding the Reaction**: - We need to convert an alkyne (which has a triple bond) into an alkene (which has a double bond) through hydrogenation. This process involves the addition of hydrogen (H₂) across the triple bond. 2. **Analyzing the Options**: - **Option A: Raney Nickel**: - Raney nickel is a catalyst that can reduce alkynes to alkanes (single bonds) rather than stopping at the alkene stage. Therefore, this option is not suitable for our purpose. - **Option B: Anhydrous AlCl₃**: - Anhydrous aluminum chloride (AlCl₃) is primarily used as a Lewis acid in electrophilic aromatic substitution reactions and does not facilitate the hydrogenation of alkynes. Thus, this option is also not suitable. - **Option C: Palladium**: - Palladium is a strong catalyst for hydrogenation. However, it tends to reduce alkynes all the way to alkanes rather than stopping at alkenes. Therefore, this option does not meet our requirement. - **Option D: Lindlar's Catalyst**: - Lindlar's catalyst is a specific catalyst used for the partial hydrogenation of alkynes to alkenes. It consists of palladium deposited on calcium carbonate and is poisoned (usually with lead or sulfur) to prevent complete hydrogenation to alkanes. This makes it the correct choice for our reaction. 3. **Conclusion**: - The correct answer is **Lindlar's Catalyst**, as it effectively reduces alkynes to alkenes without further reduction to alkanes. ### Final Answer: **D: Lindlar's Catalyst**

To solve the question "Alkyne can be reduced to alkenes by hydrogenation in presence of," we will analyze the options provided and determine which one is suitable for the reduction of alkynes to alkenes. ### Step-by-Step Solution: 1. **Understanding the Reaction**: - We need to convert an alkyne (which has a triple bond) into an alkene (which has a double bond) through hydrogenation. This process involves the addition of hydrogen (H₂) across the triple bond. 2. **Analyzing the Options**: ...
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Acetaldehyde can be reduced to ethane in the presence of LiAlH_4 .

Hydrogenation of alkyne is

Hydrogenation of alkenes and alkynes takes place in presence of certain catalysts. In Sabatier Senderen's reaction, the addition of hydrogen takes place I presence of Raney nickel catalyst. Platininm and palladium can also be used as catalyst and used in finley divided state. Experimentally, it is observed that less crowded alkenes adsorb H_(2) with faster rate. Controlled hydrogenation of alkyne H_(2) with faster rate. Controlled hydrogenation of alkyne in presence of Lindlar's catalyst yields cis product i.e., 'cis' alkene. Thus, in presence of Lindlar's catalyst 'syn' addition takes place. The relative rate of hydrogenation follows the order: Non-terminal alkynes are reduced in presence of Na or Li metal dissolved in liquid ammonia. In this reaction, anti-addition of hydrogen results into the trans-product. Answer the following questions: The relative rate of catalytic hydrogenation of following alkenes is:

Hydrogenation of alkenes and alkynes takes place in presence of certain catalysts. In Sabatier Senderen's reaction, the addition of hydrogen takes place I presence of Raney nickel catalyst. Platininm and palladium can also be used as catalyst and used in finley divided state. Experimentally, it is observed that less crowded alkenes adsorb H_(2) with faster rate. Controlled hydrogenation of alkyne H_(2) with faster rate. Controlled hydrogenation of alkyne in presence of Lindlar's catalyst yields cis product i.e., 'cis' alkene. Thus, in presence of Lindlar's catalyst 'syn' addition takes place. The relative rate of hydrogenation follows the order: Non-terminal alkynes are reduced in presence of Na or Li metal dissolved in liquid ammonia. In this reaction, anti-addition of hydrogen results into the trans-product. H_(3)C-C-=C-CH_(3)+H_(2) overset(Pd//CaCO_(3))underset("Boiling Quinoline")to (A) The product (A) will be:

Hydrogenation of alkenes and alkynes takes place in presence of certain catalysts. In Sabatier Senderen's reaction, the addition of hydrogen takes place I presence of Raney nickel catalyst. Platininm and palladium can also be used as catalyst and used in finley divided state. Experimentally, it is observed that less crowded alkenes adsorb H_(2) with faster rate. Controlled hydrogenation of alkyne H_(2) with faster rate. Controlled hydrogenationof alkyne in presence of Lindlar's catalyst yields cis product i.e., 'cis' alkene. Thus, in presence of Lindlar's catalyst 'syn' addition takes place. The relative rate of hydrogenation follows the order: Non-terminal alkynes are reduced in presence of Na or Li metal dissolved in liquid ammonia. In this reaction, anti-addition of hydrogen results into the trans-product. The product of the following reaction is:

The oxide which can be reduced by hydrogen is :

A2Z-HYDROCARBONS-Method of Preparation of Alkynes
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  2. CH(3)CH(2)C-=CH overset(A)(Leftrightarrow)CH(3)C-=CH(3) A and B resp...

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  3. Alkyne can be reduced to alkenes by hydrogenation in presence of

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  4. Westrosol has the following formula

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  5. The compounds A and B in the sequence CH-=CH+H(2)O overset(H(2)SO(4),...

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  10. Which is the most suitable reagent amon the following to ditinguish co...

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  11. Acetylene gives

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  13. Acetylene trimerises to give benzene. The reaction occurs in the prese...

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  14. Acetylene reacts with CO and H(2)O to form acrylic acid in the presenc...

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  16. HC-= CH on treatment with NH(3) in the presence of FE- pyrite produces...

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  17. Acetylene reacts with HCN in the presence of Ba(CN)(2) to yield :

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