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The product C is CH(3).CH(2).C-=CH+HC...

The product `C` is
`CH_(3).CH_(2).C-=CH+HCl rarrBoverset(HI)rarrC`

A

B

C

D

`CH_(3).underset(Cl)underset(|)(C)HCH_(2).CH_(2)I`

Text Solution

Verified by Experts

The correct Answer is:
c

This reaction occurs according to Markovnikov's rule which states that when an unsymmetrial alkene undergo hydrohalogenatio, the negative part goes to that `C-`atom which contain lesser no. of `H-` atom.
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