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CH(3)underset(CH(3))underset(|)CHCH=CH(2...

`CH_(3)underset(CH_(3))underset(|)CHCH=CH_(2)overset(HBr)rarrA`
A (predominantly) is

A

`CH_(3) - underset(CH_(3))underset(|)overset(Br)overset(|)(C )-CH_(2)CH_(3)`

B

`CH_(3) - underset(Br)underset(|)(C )H-underset(CH_(3))underset(|)(C )H-CH_(3)`

C

`CH_(3) - underset(CH_(3))underset(|)(C )H-underset(Br)underset(|)(C )H = CH_(3)`

D

`CH_(3) - underset(CH_(3))underset(|)(C )H-CH_(2)-CH_(2)Br`

Text Solution

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The correct Answer is:
a
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