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(CH(3))(2)C=CHCH(3)+NOBr rarr Product . ...

`(CH_(3))_(2)C=CHCH_(3)+NOBr rarr` Product . The structure of the product is

A

`(CH_(3))_(2)C(NO)-CH(Br)CH_(3)`

B

`(CH_(3))_(2)C(Br)-CH(NO)CH_(3)`

C

`(CH_(3))_(2)CH-C(NO)(Br)CH_(3)`

D

Text Solution

Verified by Experts

The correct Answer is:
b
The reaction follows Markownikoff rule, namely the bromide ion adds on to the carbon having the least number of hydrogen and the more positive part namely the `-NO` group adds to the other carbon of the double bond.
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