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In the figure, AB=AD and BC=DC (i) State...

In the figure, AB=AD and BC=DC (i) State three pairs of equal parts in `triangle ABC` and `triangle ADC` (ii) Is `triangle ABC ~=triangle ADC`? Give reasons (iii) Does AC bisect `angle BAD`? Give reasons

Text Solution

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AB=AD
BC=DC
1)In`/_ABC` and `/_ADC`
AB=AD
BC=DC
AC=AC
2)`/_ABC cong /_ADC`(SSS)
3)`/_BAC=/_DAC`
...
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