If `f(x)=x-4x` where `-2<=x<=3` then the range of function f is

Let f:(2,4)->(1,3) where f(x) = x-[x/2] (where [.] denotes the greatest integer function).Then f^-1 (x) is

Let f(x) = x + 2, where x le 1 and f(x) = 4x - 1 , when x gt 1 , then :

The solution set of f'(x)>g'(x) where f(x)=((1)/(2))5^(2x+1) and g(x)=5^(x)+4x log5