" cot "theta=(2tan+1/2)/(1-tan^(2)+1/2)" then "sin3 theta=

cot theta=(2tan7(1)/(2^(@)))/(1-tan^(2)7(1)/(2^(@))) then sin3 theta=

If theta=30o, verify that: (i) tan2 theta=(2tan theta)/(1-tan^(2)theta)( ii) sin2 theta=(2tan theta)/(1+tan^(2)theta)

Show that (sin^2 theta)/(1-cot theta)+(cos^2 theta)/(1-tan theta )=1+sin theta cos theta

theta = tan^(-1) (2 tan^(2) theta) - tan^(-1) ((1)/(3) tan theta) " then " tan theta=

Find, theta =tan^(-1) (2 tan^(2) theta) - tan^(-1) ((1)/(3) tan theta) " then " tan theta=

theta = tan^(-1) (2 tan^(2) theta) - tan^(-1) ((1)/(3) tan theta) " then " tan theta=

theta = tan^(-1) (2 tan^(2) theta) - tan^(-1) ((1)/(3) tan theta) " then " tan theta=

Prove each of the following identities : (1+ tan^(2) theta)(1+ cot^(2) theta)=(1)/((sin^(2) theta- sin^(4) theta))

The numerical value of 1/(1+cot^2 theta) + (3)/(1 + tan^2 theta) + 2 sin^2 theta will be

Prove that : tan theta - cot theta = (2 sin^(2) theta - 1)/(sin theta cos theta)