[" Enthalpies of solution of "BaCl_(2)(s)" and "BaCl_(2),2H_(2)O(s)" are "-20kJ/mole" and "8.0kJ/mole" respectively "],[" Calculate heat of hydration of "BaCl_(2)(s).]

Enthalpies of solution of BaCl_(2)(s) and BaCl_(2).2H_(2)O(s) are -20 kJ//"mole" and 8.0kJ//"mole" respectively. Calculate heat of hydration of BaCl_(2)(s) .

The enthalpy of dissolution of BaCl_(2)(s) and BaCl_(2).2H_(2)O are -20.6 and 8.8 KJ mol^(-1) respectively . Calculate enthalpy of hydration forgiven reaction: BaCl_(2)(s)+2H_(2)OtoBaCl_(2).2H_(2)O(s)

Ethalpies of solution of BaCI_(2)(s) and BaCI_(2).2H_(2)O(s) are -20.0kJ mol^(-1) and 8.0 kJ mol^(-1) , respectively. Calculate Delta_(hyd)H^(Theta) of BaCI_(2) to BaCI_(2).2H_(2)O .

Ethalpies of solution of BaCI_(2)(s) and BaCI_(2).2H_(2)O(s) are -20.0kJ mol^(-1) and 8.0 kJ mol^(-1) , respectively. Calculate Delta_(hyd)H^(Theta) of BaCI_(2) to BaCI_(2).2H_(2)O .

The enthalpy of solution of BaCl_(2)(s) and BaCl_(2).2H_(2)O(s) " are " -20.6 and 8.8 KJ mol^(-1) , respectively, The enthalpy change for the reaction BaCl_(2(s)) + 2H_(2)O rarr BaCl_(2), 2H_(2)O_((s)) is:

Enthalpies of solution of BaCI_(2). 2H_(2)O and BaCI_(2) are 8.8 and -20.6 kJ mol^(-1) respectively.Calculate the heat of hydration of BaCI_(2). 2H_(2)O

The heat of solution of BaCl_(2) .2H_(2) O_((s)) and anhydrous BaCl_(2(s)) are 8.37" kJ mol"^(–1) and –20.62" kJ mol"^( –1) respectively then heat of hydration of BaCl_(2(s)) will be :-