Malachite on calcination gives `rarr ‘A’ +CO_(2) +H_(2)O`. Compound `‘A’` on reduction with carbon gives `rarr CO+ ‘B’`. Here ‘A’ and ‘B’are:

Valachite on calcination gives rarr 'A' + CO_(2) +H_(2)O . Compound 'A' on reduction with carbon gives rarr CO +'B' Here 'A' and 'B' are

In a reaction, H_(2)O +C rarr CO +H_(2)

KO_(2) + CO_(2) + H_(2)O underset(CO_(2))overset("more")(rarr) A + B , then A and B are respectively

KO_(2) + CO_(2) + H_(2)O underset(CO_(2))overset("more")(rarr) A + B , then A and B are respectively

Na_(2)CO_(3)+H_(2)O+CO_(2)rarr(A). White crystalline powder (A) on reaction with phenolphthalein gives

Na_(2)CO_(3)+H_(2)O+CO_(2)rarr(A). White crystalline powder (A) on reaction with phenolphthalein gives

In the reaction C_(2)O_(4)^(2-)+MnO_(4)^(-)+H^(+) rarr Mn^(2+)+CO_(2)+H_(2)O the reductant is

At high temperature, carbon reacts with water to produce a mixture of CO and H_(2) . C + H_(2) O overset ("Heat heat")rarr CO + H_(2) CO is separated from H_(2) and then used to separate Ni from CO by forming a volatile compound, nickel tetracarbonyl (Ni(CO)_(4)) . Ni + 4CO rarr Ni(CO)_(4) (a) Formation of volatile Ni(CO)_(4) and its subsequent heating give pure Ni . Name the process involved. (b) How many moles of Ni(CO)_(4) could be obtained from CO produced by the reaction of 75.0 g is carbon ?