If the area of the triangle formed by the lines `x=0, y = 0,3x +4y- a(a >0)` is 1, then `a=` (A) `sqrt6` (B) `2sqrt6` (C) `4sqrt6` (D) `6sqrt2`

Area of the triangle formed by the lines 2x-y=6 and 3x^(2)-4xy+y^(2)=0 is

Area of the triangle formed by the lines 3x^(2)-4xy+y^(2)=0, 2x-y=6 is

The triangle formed by the line x+sqrt3y=0, x- sqrt3y=0 and x=4 is-

The triangle formed by the lines sqrt(3)x+y-2=0,sqrt(3)x-y+1=0,y=0

The equation of the circumcircle of the triangle formed by the lines y + sqrt(3)x = 6, y - sqrt(3) x = 6 and y = 0 , is-

the length of intercept made by the line sqrt2x-y-4sqrt2=0 on the parabola y^2=4x is equal to (a) 6sqrt3 (b) 4sqrt3 (c) 8sqrt2 (d) 6sqrt2

the length of intercept made by the line sqrt2x-y-4sqrt2=0 on the parabola y^2=4x is equal to (a) 6sqrt3 (b) 4sqrt3 (c) 8sqrt2 (d) 6sqrt2

If m_(1) and m_(2) are the roots of the equation x^(2) + ( sqrt(3) + 2) x + sqrt(3) - 1 =0 then prove that area of the triangle formed by the lines y=m_(1) x, y=m_(2) x and y=c is (c^2)/( 4) ( sqrt(33) + sqrt(11)) .

The equation of the circumcircle of the triangle formed by the lines y+sqrt(3)x=6,y-sqrt(3)x=6 and y=0, is-