Consider a loop ABCDEFA. With coordinates A (0, 0, 0), B(5, 0, 0), C(5, 5, 0), D(0, 5, 0) E(0, 5, 5) and F(0, 0, 5). Find magnetic flux through loop due to magnetic field ` vecB = 3 hati+4 hatk`

A loop ABCDEFA of straight edges has a six corner points A(0, 0, 0), B(5, 0, 0), C(5, 5, 0), D(0, 5, 0), E(0, 5, 5), F(0, 0, 5). The magnetic field in this region is vecB=(3hati + 4hatk)T . The quantity of the flux through the loop ABCDEFA (in Wb) is ......

Consider the points A(0, 0, 0), B(5, 0, 0), C(3, 0, 4) and D(0, 4, 3). The line AC and BD are-

Consider the points A(0, 0, 0), B(5, 0, 0), C(3, 0, 4) and D(0, 4, 3). The points A, B, C and D are-

|{:(5,-3,0),(-3,5,0),(0,0,2):}| =

A loop made of straight edegs has six corners at A(0,0,0), B(L, O,0) C(L,L,0), D(0,L,0) E(0,L,L) and F(0,0,L) . Where L is in meter. A magnetic field B = B_(0)(hat(i) + hat(k))T is present in the region. The flux passing through the loop ABCDEFA (in that order) is

A loop made of straight edges has six corners at A(0,0,0), B(L, O,0), C(L,L,0), D(0,L,0), E(0,L,L) and F(0,0,L) . Where L is in meter. A magnetic field B = B_(0)(hat(i) + hat(k))T is present in the region. The flux passing through the loop ABCDEFA (in that order) is

A loop made of straight edegs has six corners at A(0,0,0), B(L, O,0) C(L,L,0), D(0,L,0) E(0,L,L) and F(0,0,L) . Where L is in meter. A magnetic field B = B_(0)(hat(i) + hat(k))T is present in the region. The flux passing through the loop ABCDEFA (in that order) is