If `overlinea,overlineb` are unit vectors then unit vector along bisector of `DeltaAOB` is `(overlinea+overlineb)/(|overlinea+overlineb|) or ((a+hatb))/(+-|a+hatb|` Vector along internal angular bisector is `+-lambda(overlinea/|overlinea|+overlineb/|b|)`

overlineA xx overline B = overlineB xx overline A or not?

IF overlinea,overlineb,overlinec are noncoplanar, find the point of intersection of the line passing through the points 2overlinea+3overlineb-overlinec,3overlinea+4overlineb-2overlinec with the line joining the points overlinea-2overlineb+3overlinec,overlinea-6overlineb+6overlinec

For any three vectors overlinea,overlinebandoverlinec,(overlinea-overlineb).[(overlineb+overlinec)times(overlinec+overlinea)] is equal to :

IF overlinea+overlineb+overlinec=overline0,|overlinea|=3|overlineb|=5 and |overlinec|=7 , then find the between overline a and overlineb .

Let overlinea and overlineb be vectors, satisfying |overlinea|=|overlineb|=5 and (overlinea,overlineb)=45^@ . Find the area of the triangle having overlinea-2overlineb and 3overlinea+2overlineb as two of its sides.

IF overlinea,overlineb,overlinec are non-coplanar, then prove that the points with position vectors 2overlinea+3overlineb-overlinec,overlinea-2overlineb+3overlinec,3overlinea+4overlineb-2overlinec,overlinea-6overlineb+6overlinec are coplanar.

If overline a,overline b,overline c are vectors of length 4, 4, 5 re-spectively, and overline a,overline b,overline c are perpendicular to overlineb +overline c,c+overlinea, overlinea + overlineb, then |overlinea+overlineb+overlinec|=

Let overlinea=overlinei+2overlinej+3overlinek & overlineb=3overlinei+overlinej . Find a unit vector in the direction of overlinea+overlineb

IF overlinea=overlinei+2overlinej-3overlinek and overlineb=3overlinei-overlinej+2overlinek then show that overlinea+overlineb and overlinea-overlineb are perpendicular to each other.

In the Boolean algebra : overlineA*overlineB is equal to :