सरल कीजिए : ` (1 + tan^(2) theta ) (1-sin theta) (1 + sin theta)`

Explanation

`(1 + tan ^(2) theta ) (1 - sin theta ) `
`(1 + tan ^(2) theta ) (1 - sin theta ) (1 + sin theta)`
` (1 + tan ^(2)theta ) [ (1)^(2) - (sin theta)^(2)]= (1 + tan ^(2) theta (1- sin^(@) theta)`
` = sec^(2) theta . Cos^(2) theta " " ` (असमिकाओ `sec^(2) theta = 1 + tan ^(2) theta " और" sin^(2) theta + cos^(2) theta = 1` से )
` (1)/(cos^(2) theta) . cos^(2) theta = 1`