सिद्ध कीजिए कि : `(1 + cos theta - sin ^(2) theta )/(sin theta + sin theta cos theta )= cot theta `

Explanation

L.H.S = `(1 cos theta - 2 sin ^(2) theta )/(sin theta + sin theta cos theta ) = ((1 - sin^(2) theta) + cos theta)/(sin theta (1 + cos theta)) = (cos^(2) theta + cos theta )/(sin theta (1 + cos theta))`
`( cos theta (cos theta + 1))/(sin theta (1 + cos theta)) = (cos theta)/(sin theta) = cot theta = R.H.S` .