यदि ` tan theta = (4)/(3) `, तो `(3 sin theta - 2 sin ^(2) theta )/(sin theta + sin theta cos theta ) = ((1 - sin^(2) theta) + cos theta)/(sin theta (1 + cos theta)) = (cos^(2) theta + cos theta )/(sin theta (1 + cos theta))` का मान ज्ञात कीजिए |

Explanation

`(3 sin theta - 2 sin ^(2) theta )/(sin theta + sin theta cos theta ) = (3(sin theta)/(cos theta ) - 2(cos theta )/(costheta ))/(3(sin theta)/(cos theta ) +5 (cos theta )/(costheta ))" " ` ( अंश और हर को ` cos theta ` से भाग देने पर )
` (3 tan theta - 2 )/(2 tan theta + 5) = (3 xx(4)/(3) - 2 )/(3xx(4)/(3) + 5 ) = (4 - 2)/(4 + 5) = (2)/(9)`