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The points of intersection of the two cu...

The points of intersection of the two curves `|z-3|=2` and `|z|=2` in an argand plane are:

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`Z=x+iy`
`|z|=sqrt(x^2+y^2)=2`
`x^2+y^2=2`
`Z-3=x+iy-3=(x-3)+iy`
`|z-3|=sqrt((x-3)^2+y^2)=2`
`(x-3)^2+y^2=4-(2)`
`cx^2-(x-3)^2=0`
`x^2=(x-3)^2`
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