If `f : R->R` is continuous such that `f(x + y) =f(x). f(y) AA x, y in R and f(1)=2,` then `f(100)=`

If f : R to R is continuous such that f(x + y) = f(x) + f(y) x in R , y in R and f(1) = 2 then f(100) =

Let f(x+y)+f(x-y)=2f(x)f(y)AA x,y in R and f(0)=k, then

Let f(x+y)+f(x-y)=2f(x)f(y) AA x,y in R and f(0)=k , then

Let f:R->R be a function such that f(x+y)=f(x)+f(y),AA x, y in R.

Let f:R->R be a function such that f(x+y)=f(x)+f(y),AA x, y in R.

Let f:R rarr R be a function such that f(x+y)=f(x)+f(y),AA x,y in R

f((x)/(y))=f(x)-f(y)AA x,y in R^(+) and f(1)=1, then show that f(x)=In x

If f : R to R is defined as f (x+ y) = f (x) + f (y) AA x, y in R and f (1) = 7, then find sum _(r =1) ^(n) f (r).