In the figure if `I_(L)=0.8A, l_(C)=0.6A`, then I=?

In the circuit shown in the figure X_(L)=(X_(C))/(2))=R the peck value current i_(0) is

In figure i_(1) = 10 e^(-2t) A, i_(2) = 4 A, v_(C ) = 3 e^(-2t) V The current i_(L) is

In Figure,if l_(1)l_(2), what is the value of x?90^(@) (b) 85^(@)(c)75^(0)(d)70^(0)

In a part of ac circuit shown in the figure, R=0.2 Omega. At the instant shown, V_(A)-V_(B)=0.5V,i=0.5A, (di)/(dt)=8A//s . The inductance L is

Figure shows an LCR circuit. When the switch is closed, the currents through resistor R , inductor L , and capacitor C are I_(1),I_(2) , and I_(3) , respectively. Determine the values of I_(1),I_(2) , and I_(3) . a. at t = 0 b. at t = oo

Figure shows an LCR circuit. When the switch is closed, the currents through resistor R , inductor L , and capacitor C are I_(1),I_(2) , and I_(3) , respectively. Determine the values of I_(1),I_(2) , and I_(3) . a. at t = 0 b. at t = oo

Graph of a function y=f(x) is shown in the adjacent figure.Four limits l_(1),l_(2),l_(3) and I_(4), are given as:

In the circuit shows in the figure, the input voltage V_(i) is 20 V, V_(BE)=0 and V_(CE)=0 . The values of l_(B), l_(C) and beta are given by