निम्नलिखित के हरों का परिमेयकरण कीजिए :
(i) `1/(sqrt(7))` , (ii) `1/(sqrt(7) - sqrt(6))`
(iii) `1/(sqrt(5) + sqrt(2))` , (iv) `1/(sqrt(7) - sqrt(2))`

Explanation

(i) `1/(sqrt(7)) = (1)/(sqrt(7)) xx (sqrt(7))/(sqrt(7)) = (sqrt(7))/(7)`
(ii) `1/(sqrt(7) - sqrt(6)) = 1/(sqrt(7) - sqrt(6)) xx (sqrt(7) + sqrt(6))/(sqrt(7) + sqrt(6))`
`= (sqrt(7) + sqrt(6))/((sqrt(7))^(2) - (sqrt(6))^(2))`
`= (sqrt(7) + sqrt(6))/(7-6) = sqrt(7) + sqrt(6)`
(iii) `(1)/(sqrt(5) + sqrt(2)) = 1/(sqrt(5) +sqrt(2)) xx (sqrt(5) - sqrt(2))/(sqrt(5) - sqrt(2))`
`= (sqrt(5) - sqrt(2))/((sqrt(5))^(2) - (sqrt(2))^(2))`
`= (sqrt(5) - sqrt(2))/(5-2) = 1/3(sqrt(5) - sqrt(2))`
(iv) `1/(sqrt(7) -2) = 1/(sqrt(7) - 2) xx (sqrt(7) + 2)/(sqrt(7) +2)`
`= (sqrt(7) +2)/(7-4) = 1/3(sqrt(7) + 2)`