(" ii ")((x^(a))/(x^(b)))^(1/ab)((x^(b))/(x^(c)))^(1/bc)((x^(c))/(x^(a)))^(1/ac)=1

((x^(a))/(x^(b)))^(1/ab)*((x^(b))/(x^(c)))^(1/bc)*((x^(c))/(x^(a)))^(1/ca)=? a.11 b.x^(1/abc) c.x^(1/(ab+bc+ca)) d.None of these

Assuming that x is a positive real number and a,b,c are rational numbers,show that: ((x^(a))/(x^(b)))^((1)/(ab))((x^(b))/(x^(c)))^((1)/(bc))((x^(c))/(x^(a)))^((1)/(ac))=1

((x^(a))/(x^(b)))^(a+b-c)*((x^(b))/(x^(c)))^(b+c-a)*((x^(c))/(x^(a)))^(c+a-b)= a.1 b.x^(abc) c.x^(ab+bc+ca) d.x^(a+b+c)

The value of ((x^(a))/(x^(b)))^((1)/(ab)) xx ((x^(b))/(x^(c)))^((1)/(bc)) xx ((x^(c))/(x^(a)))^((1)/(ca)) is equal to

Assuming that x is a positive real number and a ,\ b ,\ c are rational numbers, show that: ((x^a)/(x^b))^(1/(a b))\ ((x^b)/(x^c))^(1/(b c))\ \ ((x^c)/(x^a))^(1/(a c))=1

Simplify: (i)\ ((x^(a+b))/(x^c))^(a-b)\ ((x^(b+c))/(x^a))^(b-c)\ ((x^(c+a))/(x^b))^(c-a) (ii)\ ((x^l)/(x^m))^(1/(lm))\ xx\ ((x^m)/(x^n))^(1/(mn))\ xx\ \ ((x^n)/(x^l))^(1/(ln))

(x^(b)/x^(c ))^(1/(bc))xx(x^(c )/x^(a))^(1/(ca))xx(x^(a)/x^(b))^(1/(ab))

For any positive real number x;write the value of {(x^(a))^(b)}^((1)/(ab)){(x^(b))^(c)}^((1)/(bc)){(x^(c))^(a)}^((1)/(ca))