" 6.(i) "(3e^(2x))/(1+e^(4x))

Integrate the following with respect to x. (i) (e^(2x) - 1)/(e^x) " " (ii) e^(3x)(e^(2x - 1)) .

int(e^(4x)-1)/(e^(2x))dx

The solution of the differential equation (dy)/(dx) = (3e^(2x) + 3e^(4x) )/( e^(x) + e^(-x) ) is a) y= e^(3x) + C b) y=2e^(2x) + C c) y= e^(x) + C d) y= e^(4x) + C

Evaluate : int (2e^(4x)-3e^(2x)+4)/(e^(3x))dx

If y=tan^(-1)((e^(2x)+1)/(e^(2x)-1)) , prove that : dy/dx=-(2e^(2x))/(1+e^(4x)) .

Statement -1 : If I_(1)=int(e^(x))/(e^(4x)+e^(2x)+1)dx and I_(2)=int(e^(-x))/(e^(-4x)+e^(-2x)+1)dx , then I_(2)-I_(1)=(1)/(2)log((e^(2x)-e^(x)+1)/(e^(2x)+e^(x)+1))+C where C is an arbitrary constant. Statement -2 : A primitive of f(x) =(x^(2)-1)/(x^(4)+x^(2)+1) is (1)/(2)log((x^(2)-x+1)/(x^(2)+x+1)) .

Statement -1 : If I_(1)=int(e^(x))/(e^(4x)+e^(2x)+1)dx and I_(2)=int(e^(-x))/(e^(-4x)+e^(-2x)+1)dx , then I_(2)-I_(1)=(1)/(2)log((e^(2x)-e^(x)+1)/(e^(2x)+e^(x)+1))+C where C is an arbitrary constant. Statement -2 : A primitive of f(x) =(x^(2)-1)/(x^(4)+x^(2)+1) is (1)/(2)log((x^(2)-x+1)/(x^(2)+x+1)) .

int (e ^ (3x) + e ^ (x)) / (e ^ (4x) -e ^ (2x) +1) dx

If I=int(e^x)/(e^(4x)+e^(2x)+1) dx. J=int(e^(-x))/(e^(-4x)+e^(-2x)+1) dx. Then for an arbitrary constant c, the value of J-I equal to