A force of 5 N gives a mass `m_(1)` an acceleration of `8m//s^(2)` and a mass `m_(2)` an accleration of 24 `m//s^(2)`. What acceleration would it give if both the masses are tied together?

Explanation

In the first case, force (F)=5N, mass (m)=`m_(1)`, acceleration (a) `=8m//s^(2)`
`because F=ma therefore 5=m_(1)xx8" or ",m=(5)/(8)kg`
`therefore` The mass, `m_(1)` is `(5)/(8)` kg.
In the second case, force (F)=5N, mass (m)=`m_(2)`, acceleration (a)=`24m//s^(2)`
`because F=ma" "therefore 5=m_(2)xx24" "therefore m_(2)=(5)/(24)kg`
`therefore`The mass `m_(2)` is `(5)/(24)` kg.
In the third case, mass`(m)=m_(1)+m_(2)=((5)/(8)+(5)/(24))kg=((15+5)/(24))kg=(20)/(24)kg=(5)/(6) kg`
Foce (F)=5N
Acceleration (a)=?
`because F=ma" "therefore 5=(5)/(6)xxa" "therefore a=cancel(5)xx(6)/(cancel(5))=6m//s^(2)`