The base area of a bottle is `5cm^(2)` and the depth of water in that bottle when it is completely filled is 30 cm. if density of water be 1 g/cc then calculate pressure and the thrust exerted by water at the bottom of the bottle. (Given `g=980cm//s^(2)`)

Explanation

Here, depth of water `(h)=30cm`
density of water (d)=1g /cc
acceleration due to gravity (g)=`980cm//s^(2)`
area of the base (A)=`5cm^(2)` ltBrgt `therefore`Pressure of water at the bottom of the bottle,
`P=hdg=30xx1xx980=29400"dyne"//cm^(2)`
Thrust exerted at the bottom=pressure`xx`Area=(29400`xx`5)dyne=147000 dyne
`therefore`Pressure at the bottom=`29400"dyne"//cm^(2)`
and thrust at the bottom=147000 dyne.