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When a tensile force of 60 N is applied ...

When a tensile force of 60 N is applied to a metal wire of length 50 m and ara of cross- section `10^(-6)m^(2)`, elengation of the wire is `4xx10^(-3)`m. calculate (i) stress and (ii) strain.

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Hence, force `(F)=60N`, area of cross-section `(A)=10^(-6)m^(2)`
original length of the wire (l)=5m
Expansion in length `(Deltal)=4xx10^(-3)m`.
`therefore (i)` Stress `=(F)/(A)=(60)/(10^(-6))N//m^(2)=6xx10^(7)N//m^(2)`
(ii) Strain`=(Deltal)/(l)=(4xx10^(-3))/(5)=0.8xx10^(-3)=8xx10^(-4)`
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