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(Mole to Mole calculation) How many mo...

(Mole `to` Mole calculation)
How many moles of `NH_(3)` can be produced from 2.0 mol `H_(2)` in the reaction
`N_(2)(g)+3H_(2)(g) to 2NH_(3)(g)`?

Text Solution

Verified by Experts

From the balanced chemcial equation, we see that 3 mol `H_(2)` reacts (with 1 mol `N_(2)`) to give 2 mol `NH_(3)" "therefore` 2.0 mol of `H_(2)=(2)/(3)xx2=(4)/(3)=1.33" mol of "NH_(3)`.
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