(1+tan alpha*tan beta)^(2)+(tan alpha-tan beta)^(2)=sec^(2)alpha*sec^(2)beta

Prove the following identity: (1+tan alpha tan beta)^(2)+(tan alpha)(tan alpha-tan beta)^(2)=sec^(2)alpha sec^(2)beta

What is (1+tan alpha tan beta)^2+(tan alpha-tan beta)^2-sec^2 alpha" "sec^2beta equal to?

The value of tan^(2)alpha-tan^(2)beta-(1)/(2)sin(alpha-beta)sec^(2)alpha sec^(2)beta is zero if

If 2tan alpha=3tan beta then tan(alpha-beta)=

(sec alpha * sec beta + tan alpha tan beta )^(2)-( sec alpha * tan beta + tan alpha * sec beta )^(2) =

(tan alpha + tan beta )/( tan (alpha + beta ))+(tan alpha - tan beta )/(tan (alpha - beta )) =

If tan(alpha-beta)=(sin2 beta)/(3-cos2 beta), then ( i )tan(alpha)=2tan(beta)( ii) (1)/(2)tan(alpha)=tan(beta)( (ii) 2tan(alpha)=3tan(beta)( iv) 3tan(alpha)=2tan(beta)

If tan theta = ( tan alpha + tan beta)/(1 + tan alpha tan beta),"show that " sin 2 theta =(sin 2 alpha + sin 2 beta)/(1+sin 2 alpha sin 2 beta)

If tan 2alpha = cot 2beta , then sec(alpha + beta) =

If tan alpha=(1-cos beta)/(sin beta), then a )tan3 alpha=tan2 beta(b)tan2 alpha=tan beta(c)tan2 beta=tan alpha(d) none of these