A sodium `(Na)` surface is illuminated with light of wavelength `300 nm`. The work function for `Na` metal is `2.46eV`. The kinetic enegry of the ejected photoelectrons is

A metal is irradiated with light of wavelength 660 nm. Given that the work function of the metal is 1.0eV, the de Broglie wavelength of the ejected electron is close to-

A metal is irradiated with light of wavelength 600 nm. Given that the work function of the metal is 1.0 eV, the de Broglie wavelength of the ejected electron is close to:

A sodium metal piece is illuminated with light of wavelength 0.3 mum . The work function of sodium is 2.46 eV. For this situation ,mark out the correct statement (s).

A sodium metal piece is illuminated with light of wavelength 0.3 mum . The work function of sodium is 2.46 eV. For this situation ,mark out the correct statement (s).

If light of wavelength 6200Å falls on a photosensitive surface of work function 2 eV, the kinetic energy of the most energetic photoelectron will be

Surface of sodium is illuminated by a light of 6000 Å wavelength. Work function of sodium is 2.6 eV. Then minimum K.E. of emitted electron is :

Light of wavelength 200 nm incident on a metal surface of threshold wavelength 400 nm kinetic energy of fastest photoelectron will be

Light of wavelength 200 nm incident on a metal surface of threshold wavelength 400 nm kinetic energy of fastest photoelectron will be

Light of wavelength 200 nm incident on a metal surface of threshold wavelength 400 nm kinetic energy of fastest photoelectron will be

The surface of a metal is illuminated with light of wavelength 400 nm. The kinetic energy of the ejected photoelectrons was found to be 1.68 eV. What is the work function of the metal ? [ hC=1240 eV*nm ]