If `alpha and beta` are non-real, then condition for `x^(2) + alpha x + beta = 0` to have real roots, is

If alpha and beta are the roots of the equation x ^(2) + alpha x + beta = 0, then

If alpha,beta are non - real cube roots of 2, then alpha^(6) + beta^(6) equals

IF alpha , beta are the roots of x^(2)-x+2=0 then alpha ^ 2 beta + alpha beta ^2 =

If alpha and beta are the roots of x^2-2x+3=0 then alpha^2beta+ beta^2 alpha =….

If alpha, beta are the non-real cube roots of 2, then alpha^(6)+beta^(6)=

If alpha and beta are non real cube roots of unity then alpha beta+alpha^(5)+beta^(5)=

If alpha, beta are the non-real cube roots of 3 then alpha^(6)+beta^(6)=

if alpha and beta are the roots of the equatio0n x^2+px+q=0 and does not have real roots then (alpha-beta)^2 =

If alpha, beta are the roots of the equations 6x^2+11x+3=0 , then a)Both cos^(-1) alpha and cos^(-1) beta are real b)Both "cosec"^(-1) alpha and "cosec"^(-1) beta are real c)Both cot^(-1) alpha and cot^(-1) beta are real d)None of these