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Prove the following Boolean relations: ...

Prove the following Boolean relations:
`bar(A)+AB+bar(AB)=1`

Text Solution

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LHS = `bar(A) + AB + bar(AB) = bar(A) + AB + bar(A) + bar(B) = bar(A) + bar(B) + AB`
[`because bar(AB) = bar(A) + bar(B) and bar(A) + bar(A) = bar(A)`]
`=bar(A).1 + bar(B)+AB = bar(A)(1 + B) + bar(B) + AB " "[because 1 + B = 1]`
`bar(A) +bar(A)B + bar(B) +AB = bar(A) + bar(B) + (bar(A)+A)B`
=`bar(A) +bar(B) +1.B = bar(A) + (bar(B)+B) = bar(A) + 1 = 1 = RHS`
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