A radioactive element emits 2 `alpha`-particles and 3 `beta`-particles . The values of atomic number (Z) and mass number (A) of the new element will be -

(A) (A+5), (Z-1)
(B) (A-5), (Z+1)
(C) (A-8), (Z-1)
(D) (A-8), (Z+1)

Options

A. (A+5),(Z-1)
B. (A-5),(Z+1)
C. (A-8),(Z-1)
D. (A-8),(Z+1)

Answer

c

Explanation

The mass number after emission of 2 `alpha`-particles =A - (2 x 4 ) = (A-8)
The atomic number after emission of `2 alpha`-particles and 3 `beta`-particles =Z - (2 x 2) + (3 x 1) =Z -1