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Radon-222 has a half-life of 3.8 days. I...

Radon-222 has a half-life of 3.8 days. If one starts with 0.064 kg of Radon-222 the quantity of Radon-222 left after 19 days will be -

(A) 0.002 kg.
(B) 0.062 kg.
(C) 0.032 kg.
(D) 0.024 kg.

A

0.002 kg

B

0.062 kg

C

0.032 kg

D

0.024 kg

Text Solution

Verified by Experts

The correct Answer is:
A
`N/N_0=(1/2)^(t//T)`
or, `N=N_0(1/2)^(19//3.8) = 0.064xx1/32`=0.002 kg
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