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If radius of the .13^27Al nucleus is tak...

If radius of the `._13^27Al` nucleus is taken to be `R_"Al"` , then the radius of `._53^125Te` nucleus is nearly

A

`(53/13)^(1//3) R_"Al"`

B

`5/3 R_"Al"`

C

`3/5 R_"Al"`

D

`(13/53)^(1//3)R_"Al"`

Text Solution

Verified by Experts

The correct Answer is:
B
We know, `R=r_0A^(1//3)`
Then `R_"Al"=r_0(27)^(1//3)=3r_0`
`therefore R_"Te"=r_0(125)^(1//3) = 5r_0 = 5/3 .3r_0 = 5/3R_"Al"`
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CHHAYA PUBLICATION-ATOMIC NUCLEUS-EXAMINATION ARCHIVE
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  18. If radius of the .13^27Al nucleus is taken to be R"Al" , then the radi...

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