The cartesian equation of a straight li...

The cartesian equation of a straight line is `(x-3)/(4)=(y+2)/(5)=(z-4)/(3)`, its vector form will be -

`vecr=4hati+5hatj+3hatk+lambda(3hati-2hatj+4hatk)`

`vecr=-3hati+2hatj-4hatk+lambda(4hati+5hatj+3hatk)`

`vecr=3hati-2hatj+4hatk+lambda(4hati+5hatj+3hatk)`

none of these

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CHHAYA PUBLICATION-MCQ ZONE -Question Paper 6

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