If the equation of a straight line is 6x...

If the equation of a straight line is `6x-2=3y+1=2z-2`, then direction cosines of the line are -

`(1)/(sqrt(14)),(2)/(sqrt(14)),(3)/(sqrt(14))`

`(6)/(7),(3)/(7),(2)/(7)`

`-(2)/(3), (1)/(3), -(2)/(3)`

none of these

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(i) Find the vector equation of a line passing through a point with position vector 2hat(i)-hat(j)+hat(k) , and parallel to the line joining the points -hat(i)+4hat(j)+hat(k) and hat(i)+2hat(j)+2hat(k) . Also find the cartesian equivalent of this equation. (ii) The cartesian equations of a line are 6x-2=3y+1=2z-2 . Find its direction ratios and also find vector equation of the line.

CHHAYA PUBLICATION-MCQ ZONE -Question Paper 6

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