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|{:(1,bc,a(b+c)),(1,ca,b(c+a)),(1,ab,c(a...

`|{:(1,bc,a(b+c)),(1,ca,b(c+a)),(1,ab,c(a+b)):}|=0`

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The correct Answer is:
`=(ab+bc+ca)xx0[because` 1 st and 3rd columns are identical ] =0
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