|{:((a+1)(a+2),a+2,1),((a+2)(a+3),a+3,1)...

`|{:((a+1)(a+2),a+2,1),((a+2)(a+3),a+3,1),((a+3)(a+4),a+4,1):}|=-2`

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Use product {:[( 1,1,2),( 0,2,3),( 3,2,4) ]:} {:[( 2,0,1),(9,2,3),(6,1,2) ]:} to solve the system of equations x-y+2z=1 xy-3z=1 3x-2y+4z =2

Let A ={1,2,3,4} and relation R on A be defined as follows: R = (1,2),(2,1),( 2,2),(2,3) ,(3,3) ,(4,1), (2,4),(4,2)} then which one of the following is correct ?

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Let the relation R on set A = {1,2,3,4,5} be defined as follows: R={(1,2),(2,1),(2,2),(3,3),(4,1),(2,4),(4,2),(1,5),(5,1),(5,5)} Then state which one is true in each of the following two cases

If A=[((2)/(3), 1,(5)/(3)),((1)/(3), (2)/(3), (4)/(3)),((7)/(3), 2, (2)/(3))] and B=[((2)/(5), (3)/(5), 1),((1)/(5), (2)/(5), (4)/(5)),((7)/(5),(6)/(5),(2)/(5))] , then compute 3A-5B .

CHHAYA PUBLICATION-DETERMINANT -EXERCISE 2B

Prove |{:(1,a^2+bc,a^3),(1,b^2+ca,b^3),(1,c^2+ab,c^3):}|=-(a-b)(b-c)(c...
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|{:(a^2,a^2-(b-c)^2,bc),(b^2,b^2-(c-a)^2,ca),(c^2,c^2-(a-b)^2,ab):}|=(...
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|{:((a+1)(a+2),a+2,1),((a+2)(a+3),a+3,1),((a+3)(a+4),a+4,1):}|=-2
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Show that the following determinant is a perfact square : |{:(1,a,a^...
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if x+y+z = 0 then prove that |{:(x,y,z),(x^2,y^2,z^2),(y+z,z+x,x+y):}|...
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|{:(1,1,1),(x,y,z),(x^3,y^3,z^3):}|=0
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|{:(x," "4,-2),(4," "x,-2),(4,-2," "x):}|=0
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|{:(x,a,a),(a,x,b),(b,b,x):}|=0
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|{:(x+1," "2," "3),(" "1,x+1," "3),(" "3,-6,x+1):}|=0
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|{:(a-x," "b," "c),(" "b,c-x," "a),(" "c," "a,b-x):}|=0
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|{:(" "x," "c+x," "b+x),(" "c+x," "x," "a+x),(" "b+x," "a+x," ...
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|{:(2-x," "2," "3),(" "2,5-x," "6),(" "3," "4,10-x):}|=0
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solve:|{:(3+x,3-x,3-x),(3-x,3+x,3-x),(3-x,3-x,3+x):}|=0
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|{:(x-2,2x-3,3x-4),(x-4,2x-9,3x-16),(x-8,2x-27,3x-64):}|=0
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|{:(0,x-a,x-b),(x+a,0,x-c),(x+b,x+c,0):}|=0[where" "a neb nec]
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Solve: |{:(3,5,x),(7,x,7),(x,5,3):}|=0
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|{:(x+a," "b," "c),(" "a,x+b," "c),(" "a," "b,x+c):}|=0
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|{:(3x-8," "3," "3),(" "3,3x-8," "3),(" "3," "3,3x-8):}|=0
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|{:(15-2x,11-3x,7-x),(11,17,14),(10,16,13):}|=0
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|{:(" "1," "1," "x),(p+3,p+1,p+x),(" "3,x+1,x+1):}|=0
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