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x+y+z=1, ax+by+cz=k, bcx+cay+abz=k^2...

x+y+z=1, ax+by+cz=k, bcx+cay+abz=`k^2` [a,b,c are unequal ]

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The correct Answer is:
`x=(k^2+ak-a(b+c))/((a-b)(a-c)),y=(k^2bk-b(c+a))/((b-a)(b-c)) ,z=(k^2+ck-c(a+b))/((c-a)(c-b))`
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