Show that the equation `e^(x-1)+x-2=0` has no real root greater than 1.

The equation e^(x-1)+x-2=0 as

Show that the equation e^(x-1)+x-2=0 has no real root which is less than 1.

A quadratic trinomial P(x)=a x^2+b x+c is such that the equation P(x)=x has no real roots. Prove that in this case equation P(P(x))=x has no real roots either.

The quadratic equation x^(2)-2x+1=0 have no real root.

Let a , b , c be nonzero real numbers such that int_0^1(1+cos^8x)(a x^2+b x+c)dx =int_0^2(1+cos^8x)(a x^2+b x+c)dx=0 Then show that the equation a x^2+b x+c=0 will have one root between 0 and 1 and other root between 1 and 2.

The equation sin ^(-1)"" x=2sin ^(-1)2a has real roots if

Find the values of 'm' for which the equation x^4-(m-3)x^2+m =0 has No real roots

All the values of m for whilch both the roots of the equation x^2-2m x+m^2-1=0 are greater than -2 but less than 4 lie in the interval A -2 B. m >3 C. -1ltmlt3 D. 1ltmlt4

Find the values of the parameter a for which the roots of the quadratic equation x^2+2(a-1)x+a+5=0 are such that one root in greater than 3, and the other is smaller than 3

If the equation a x^2+b x+c=x has no real roots, then the equation a(a x^2+b x+c)^2+b(a x^2+b x+c)+c=x will have a. four real roots b. no real root c. at least two least roots d. none of these