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DIFFERENTIAL EQUATIONS OF THE FIRST ORDER AND FIRST DEGREE
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CHHAYA PUBLICATION-DIFFERENTIAL EQUATIONS OF THE FIRST ORDER AND FIRST DEGREE -PART -C
- (dy)/(dx)=(y-x)/(x+y)
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Playing Now - (dy)/(dx)=(3x+2y)/(2x-3y)
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Play - (2x+y)dy=(x-2y)dx
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Play - (dy)/(dx)=(2x+3y)/(3x+2y)
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Play - x(dy)/(dx)=y(logy-logx-1)
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Play - (dy)/(dx)+(y)/(x)=(y^(2))/(x^(2))
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Play - (x^(2)+xy)(dy)/(dx)=x^(2)+y^(2)
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Play - (1)/(2x)(dy)/(dx)+(x+y)/(x^(2)+y^(2))=0
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Play - (dy)/(dx)=(y(2y-x))/(x(2y+x))=0, given y=1, when x=1
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Play - x(x-y)dy+y^(2)dx=0
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Play - y^(2)dx+(x^(2)-xy)dy=0
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Play - x^(2)ydx-(x^(3)+y^(3))dy=0
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Play - (dy)/(dx)=(y)/(x)+cot""(y)/(x)
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Play - (dy)/(dx)=(y)/(x)-tan""(y)/(x)
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Play - x^(2)dy+(x^(2)-xy+y^(2))dx=0
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Play - (x^(2)-2xy)dy+(x^(2)-3xy+2y^(2))dx=0
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Play - y^(2)dx+(x^(2)-xy)dy=0
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Play - (dy)/(dx)=(y(y+x))/(x(y-x))
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Play - xdy-ydx=(x^(2)-3xy+2y^(2))dx=0
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Play - Solve the following differential equation xdy-ydx=sqrt(x^(2)+y^(2))dx
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