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(2x+y)dy=(x-2y)dx...

`(2x+y)dy=(x-2y)dx`

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The correct Answer is:
`x^(2)-4xy-y^(2)=c`
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The solution of (x^(2)+xy)dy=(x^(2)+y^(2))dx is

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Solve: x^(2)(x dx+y dy)+2y(x dy-y dx)=0