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A shperical toy balloon is inflated so t...

A shperical toy balloon is inflated so that its volume V (in `cm^(3)`) and surface area S (in `cm^(2)` ) are functions of time t (in second), where `V = (pi)/(6) t^(3) and S = pit^(3)`. Find the rates of change of v and S at t = 4

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The correct Answer is:
8 `pi cm^(3)//s and 8 pi cm^(2)//s`
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