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For any angle theta, the expression (2co...

For any angle `theta, `the expression `(2cos 8 theta +1)/(2 cos theta +1)` is equal to-

A

`(2 cos theta -1) (2 cos 2 theta -1) (2 cos 4 theta -1)`

B

`(2 cos theta +1 )(cos 2 theta +1) (2 cos 4 theta +1)`

C

`(cos theta -1) ( cos 2 theta -1) (cos 4 theta -1)`

D

`( 2 cos theta -1) (2 cos 2 theta -1) (2 cos 4 theta +1)`

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • 1-cos2theta =

    A
    `2sin^(2)theta`
    B
    `2cos^(2)theta`
    C
    `sin^(2)theta`
    D
    `2cos^(2)theta`

  • If sintheta + sin^2 theta=1 , then the value of the expression cos^12 theta + 3 cos^10 theta + 3 cos^8 theta + cos^6 theta -1 is

    A
    0
    B
    -1
    C
    1
    D
    2

  • (1-cos2theta)/(sin2theta)=

    A
    `sintheta`
    B
    `cos theta`
    C
    `tan theta`
    D
    none of these

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