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If the cube roots of unity are 1, omega,...

If the cube roots of unity are `1, omega, omega ^(2)` then the roots of the equation `(x-2) ^(3)+ 27=0` are-

A

`1, 2+ 3omega,3 omega ^(2)`

B

`-2, -2, 3omega , -2 -3 omega ^(2)`

C

`-1, 2-3 omega, 2 -3 omega ^(2)`

D

`1, 3- 2 omega , 3 -2 omega ^(2)`

Text Solution

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The correct Answer is:
C
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